Based on the below velocity-time graph for an object in motion along a straight line with
constant acceleration, match the Column I (description of motion) with Column If (time interval) and select the correct answer from the code given below.
With reference to the above given 
graph choose the incorrect pair.
to 
and then turns back with same negative acceleration between time interval 
to 
to 
s to 
Text Solution
Verified by ExpertsC
For 
to 
, the motion is in positive direction as the velocity is positive and the
acceleration is positive, since the slope of the straight line is positive.
For 
to 
, the object is moving in positive direction, till time 
, and then turns back with the same negative acceleration till 
.
For 
to 
, the object is moving in negative direction, since the velocity is negative. The acceleration is positive, since the slope of the straight line is positive.
Displacement for overall journey ( 
to 
) 
Total area under 
graph considering the area below time axis as negative 
Area under 
-t curve for 
to 
] + [Area under 
- 
curve for 
; to 
Area of triangle 
Area of triangle (BCD)
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